1)local mean局部均值
1.Infrared object tracking based on local mean of integral edge strength基于积分边缘强度局部均值的红外目标跟踪
2.This method mainly takes advantage of the grey level change of texture image to compare the pixel grey level value to the local mean of neighbour domain which the .此方法主要利用纹理图象的灰度变化特性,采用将像素点灰度与所在邻域内灰度的局部均值比较的方法,使原方法更有针对性。
英文短句/例句
1.Image Enhancement Algorithm Based on Local Mean and Standard Deviation基于局部均值和标准差的图像增强算法
2.Background suppression for dim small target with Gabor kernel non-local means采用Gabor核非局部均值的弱小目标背景抑制
3.Infrared object tracking based on local mean of integral edge strength基于积分边缘强度局部均值的红外目标跟踪
4.Comparison between the methods of local mean decomposition and empirical mode decomposition局部均值分解与经验模式分解的对比研究
5.Non-local Means Image Denoising in Wavelet Domain with Unknown Noise Variance噪声方差未知的小波域中非局部均值图像去噪
6.Structure-Preserving Speckle Reduction of Using Nonlocal Means Filter基于非局部均值滤波的结构保持相干斑噪声抑制方法
7.Chaotic Neural Networks and Their Application in the 2-D Adaptive Local Mean Estimation Filtering一种混沌神经网络及其在二维局部均值估计自适应滤波中的应用
8.Local Mean Decomposition Method and Its Application to Roller Bearing Fault Diagnosis局部均值分解方法及其在滚动轴承故障诊断中的应用
9.The local mean decomposition method and its application to gear fault diagnosis局部均值分解方法及其在齿轮故障诊断中的应用
10.Two-dimension Local-mean Estimator Adaptive Filter Based on Chaotic Neural Network基于混沌神经网络的二维局部均值估计自适应滤波
11.calculated average local gas气体局部平均速度计算值
12.Non-local denoising fast fuzzy C-means clustering algorithm非局部降噪快速模糊C-均值聚类算法
13.Tail Asymptotics and Local Asymptotics for the Supremum of a Random Walk with an Infinite Mean均值无限的随机游动上确界的尾渐近性和局部渐近性
14.The Dynamic Feature Analysis of Rayleigh Surface Wave on a Local Inhomogeneity Using the Numerical Method局部非均质体的瑞利面波动力学响应数值模拟研究
15.A BENDING ANALYSIS OF THE NONHOMOGENEOUS MODERATELY THICK PLATE USING THE MESHLESS LOCAL RADIAL POINT INTERPOLATION METHOD用无网格局部径向点插值法分析非均质中厚板的弯曲问题
16.NUMERICAL SIMULATION OF EFFECTIVE STIFFNESS AND LOCAL STRESSES FOR WAVY NANO-TUBE REINFORCED COMPOSITES BY THE MACRO-MICROSCOPICHOMOGENIZATION METHOD波形碳纳米管增强复合材料的有效刚度和局部应力的宏微观均质化数值模拟
17.Research on Local Lagrangian Numerical Differentiation;局部Lagrange数值微分法研究
18.General Equilibrium, Partial Equilibrium and the Model of Institutional Change;一般均衡、局部均衡与制度变迁方式转换
相关短句/例句
Non-local means非局部均值
1.Image denoising technology is one of the forelands in the field of Computer Graphic and Computer Vision; Non-local Means method is one of the great performing methods which arouse tremendous research.本文在非局部均值算法的基础上提出改进方案,针对图像自身的特点自适应的取最优参数,同时大大的减低其运算量和时间。
2.Non-local means model processes image basing on global information.本文提出一种偏微分方程约束的非局部均值图像插值模型。
3)curves of local mean value局部均值曲线
4)Degree of local mean contrast局部均值对比度
5)operator of local mean局部均值算子
6)Local mean decomposition局部均值分解
1.Comparison between the methods of local mean decomposition and empirical mode decomposition局部均值分解与经验模式分解的对比研究
2.The local mean decomposition method and its application to gear fault diagnosis局部均值分解方法及其在齿轮故障诊断中的应用
3.Two methods of time-frequency analysis, Hilbert-Huang transform (HHT) and local mean decomposition (LMD), are studied and applied in time-varying structural modal parameter identification in this paper.但大型柔性空间结构、高速飞行器和高速列车等实际工程又有迫切的需要,为此,本文在系统总结时变结构模态参数识别研究现状的基础上,主要研究了Hilbert-Huang变换(HHT)和局部均值分解(LMD)两种新的时频分析方法在时变结构模态参数识别中的应用。
延伸阅读
均值不等式几个重要不等式(一)一、平均值不等式设a1,a2,…, an是n个正实数，则，当且仅当a1=a2=…=an时取等号1.二维平均值不等式的变形(1)对实数a,b有a2+b2³2ab (2)对正实数a,b有(3)对b>0，有， (4)对ab2>0有，(5)对实数a,b有a(a-b)³b(a-b) (6)对a>0,有(7) 对a>0,有 (8)对实数a，b有a2³2ab-b2(9) 对实数a，b及l¹0，有二、例题选讲例1.证明柯西不等式证明：法一、若或命题显然成立，对¹0且¹0，取代入(9)得有两边平方得法二、，即二次式不等式恒成立则判别式例2.已知a>0,b>0,c>0,abc=1,试证明：(1)(2)证明：(1)左=[]=³(2)由知同理：相加得：左³例3.求证：证明：法一、取，有a1(a1-b)³b(a1-b), a2(a2-b)³b(a2-b),…, an(an-b)³b(an-b)相加得(a12+ a22+…+ an2)-( a1+ a2+…+ an)b³b[(a1+ a2+…+ an)-nb]³0所以法二、由柯西不等式得： (a1+ a2+…+ an)2=((a1×1+ a2×1+…+ an×1)2£(a12+ a22+…+ an2)(12+12+…+12)=(a12+ a22+…+ an2)n,所以原不等式成立例4.已知a1, a2,…,an是正实数，且a1+ a2+…+ an<1，证明：证明：设1-(a1+ a2+…+ an)=an+1>0,则原不等式即nn+1a1a2…an+1£(1-a1)(1-a2)…(1-an)1-a1=a2+a3+…+an+1³n1-a2=a1+a3+…+an+1³n…………………………………………1-an+1=a1+a1+…+an³n相乘得(1-a1)(1-a2)…(1-an)³nn+1例5.对于正整数n，求证：证明：法一、>法二、左==例6.已知a1,a2,a3,…,an为正数，且，求证：(1)(2)证明：(1)相乘左边³=(n2+1)n证明(2)左边= -n+2(= -n+2×[(2-a1)+(2-a2)+…+(2-an)](³ -n+2×n
