一种合金钢及其制备方法与流程

文档序号:12744062阅读:来源:国知局

技术特征:

1.一种合金钢,其特征在于:该合金钢的重量百分比是,0.45-0.52%的碳,0.24-0.25%的硅,0.3-0.35%的锰,0.3-0.5%的铬,0.6-1.0%的镍,0.3%的铝,0.4%的铜,0.3%的锌,0.03%的钼,0.3%的锡,0.02%的锶,0.06%的钴,0.08%的矶,0.6%的钨,0.0001%的钛,0.003%的硼余量为铁。

2.一种合金钢的制备方法,包括以下步骤:

1)按照重量百分比为0.45-0.52%的碳,0.24-0.25%的硅,0.3-0.35%的锰,0.3-0.5%的铬,0.6-1.0%的镍,0.3%的铝,0.4%的铜,0.3%的锌,0.03%的钼,0.3%的锡,0.02%的锶,0.06%的钴,0.08%的矾,0.6%的钨,0.0001%的钛,0.003%的硼余量为铁进行配料;

2)通过中频感应炉熔炼制备合金钢;

3)将合金钢进行正火和等温淬火处理;所述淬火分两阶段等温淬火,第一阶段采用采用230±20℃盐浴等温淬火处理至500-550℃,淬火速度保持在20-25℃每秒钟;第二阶段为水溶液淬火,水溶液保持在75-80℃,淬火速度保持在25-30℃每秒,淬火温度到130-150℃;然后回火处理,回火温度为180-220℃并保温2小时,然后自然冷却。

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