存储器装置的基于线性规划的解码的制作方法_4

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112(1,2)和(2,I)的干扰。因为特定读取单元实际上可能经历来自任何数量的邻近单元112的干扰,所以应该理解,这个示例是例示性的,并且不应该被以任何方式解释为限制性的。
[0069]在这个示例中,能够将阵列500的单元112的值表达为:
[0070]Y(l, I) = X(l, I)
[0071]Y(2, I) = X(2, 1)+χΧΧ(1, I)
[0072]Y (3,1)=Χ (3,I) +X X X (2,I)
[0073]Y(l,2) = X(l,2)+yXX(l, I)
[0074]Y (2,2) = X (2,2) +X X X (1,2) +y X X (2,I)
[0075]Y(3,2) = X(3,2)+χΧΧ(2,2)+yXX(2,I)
[0076]Υ(1, 3) = X(l, 3)+yXX(l, 2)
[0077]Y (2,3) = X (2,3) +X X X (1,3) +y X X (2,2)
[0078]Y(3,3) =乂(3,3)+1父乂(2,3)+7\父(3,2),其中,1和7可以是针对阵列500作为其一部分的特定存储器108测量到的值。出于例示这个示例的目的,将假定X和y分别为
0.2和0.3。因此,能够将上述值表达为:
[0079]Y(l, I) = X(l, I)
[0080]Y (2,I) = X (2,I) +0.2 X X (1,I)
[0081 ] Y (3,I) = X (3,I) +0.2 X X (2,I)
[0082]Y(l, 2) = X(l, 2)+0.3XX(1, I)
[0083]Y (2,2) = X (2,2) +0.2 X X (1,2) +0.3 X X (2,I)
[0084]Y (3,2) = X (3,2) +0.2 X X (2,2) +0.3 X X (2,I)
[0085]Y(l, 3) = X(l, 3)+0.3XX(1, 2)
[0086]Y (2,3) = X (2,3) +0.2 X X (1,3) +0.3 X X (2,2)
[0087]Y (3,3) = X (3,3) +0.2 X X (2,3) +0.3 X X (3,2)
[0088]根据一些实施方式,能够通过测量以上所阐述的电压电平Y(i,j)并且将那些与实际观测到的测量值Z(i,j)进行比较来确定干扰。出于例示的目的,假定了以下观测到的测量值Z(i,j):
[0089]Z(l, I) = 1.5
[0090]Z(l, 2) = 1.6
[0091]Z (1,3) =0.2
[0092]Z (2, I) = 1.7
[0093]Z (2, 2) = 1.1
[0094]Z (2,3) = 0.3
[0095]Z (3, I) = 1.9
[0096]Z (3,2) = 0.1
[0097]Z (3, 3) = 1.3
[0098]鉴于这些测量值和已知干扰图样,能够将本文所阐述的欧几里得距离表达为(Y(l,I) -Z (I, I))2+ (Y (2,I) -Z (2,I))2+ (Y (3,I) -Z (3,I))2+ (Y (1,2) -Z (I, 2))2+ (Y (2,2) -Z (2,2))2+(Y(3, 2)-Z (3,2))2+(Y(l, 3)-Z (I, 3))2+(Y(2,3)-Z (2,3))2+(Y(3,3)-Z (3,3))2。使用以上为这个阵列500生成的已知单元间干扰模型,能够将欧几里得距离表达为(X(l,1)-Z(1, I))2+ (X (2,I) +0.2X (1,I) -Z (2,I))2+ (X (3,I) +0.2X (2,I) -Z (3,I))2+ (X (1,2) +0.3X (1,I) -Z (I,2))2+ (X (2,2) +0.2X (1,2) +0.3X (2,I) -Z (2,2))2+ (X (3,2) +0.2X (2,2) +0.3X (2,I) -Z (3,2))2+ (X(1,3) +0.3X(I, 2)-z(l, 3))2+ (X(2,3) +0.2X(I, 3) +0.3X(2,2)-Z (2,3))2+ (X(3,3) +0.2X(2,3)+0.3X(3, 2)-Z (3,3))2。
[0099]此外,能够在欧几里得距离的上述表达式中代入以上所确定的Z(i,j)的值以获得(X(l, 1)-1.5)2+ (X(2, 1)+0.2XX(1, 1)-1.7)2+ (X(3, 1)+0.2XX(2, 1)-1.9)2+ (X(l, 2) +0.3XX(1, 1)-1.6)2+ (X(2, 2)+0.2XX(1, 2)+0.3XX(2, 1)-1.1)2+ (X(3, 2)+0.2XX(2, 2)+0.3XX(2, 1)-0.1)2+ (X(l, 3)+0.3XX(1, 2)-0.2)2+ (X(2, 3)+0.2XX(1, 3)+0.3XX(2, 2)-0.3)2+(X(3, 3)+0.2XX(2, 3)+0.3XX(3, 2)-1.3)2。此外,在一些实施方式中,能够将这个表达式的二次项扩展为(X(l, 1)-1.5)2= X(l, I) 2-3X(l, 1)+1.52= X(l, 1)_3X(1,1)+2.25=-2X(1, 1)+2.25。
[0100]参照图5能够了解,因为X(l,I)可能等于零(O)或一⑴所以X(l,1)2=X(1, I)。类似地,能够获得下式为:
[0101](I) (X(2, 1)+0.2X(1, 1)-1.7)2= X ( 2 , I ) 2+ 0.2 X ( I , I )X (2,1)-1.7X(2, 1)+0.2X(1, I) X (2,1)+0.04X(1, l)2-0.34X(1, 1)-1.7X(2, 1)-0.34X(1, 1)+1.72= X(2, 1)+0.2X(1, I)X(2, 1)-1.7X(2, 1)+0.2X(1, I)X(2, 1)+0.04X(1, 1)-0.34X(1, 1)-1.7X(2, 1)-0.34X(1, 1)+2.89 = 0.4X(1, I)X(2,1)-2.4X(2, 1)-0.64X(1, 1)+2.89
[0102](2) (X(3, 1)+0.2X(2, 1)-1.9)2= X ( 3 , I ) 2+ 0.2 X ( 2 , I )X (3,1)-1.9X(3, 1)+0.2X(3, I) X (2,1)+0.04X(2, l)2-0.38X(2, 1)-1.9X(3, 1)-0.38X(2, 1)+1.92= X(3,1)+0.2X(2, I)X(3,1)-1.9X(3, 1)+0.2X(3, I)X(2,1)+0.04X(2, 1)-0.38X(2, 1)-1.9X(3, 1)+0.38X(2, 1)+3.61 = 0.4X(2, I)X(3,1)-2.8X(3, 1)-0.34X(2, 1)+3.61
[0103](3) (X(l, 2)+0.3X(1, 1)-1.6)2= X ( I , 2) 2+0.3 X ( I , I )X(l, 2)-1.6X(1, 2)+0.3X(1, 2)X(1, 1)+0.09X(1, I)2-.8X(1, 1)-1.6X(1, 2)-0.48X(1, 1)+1.62= X(l, 2)+0.3X(1, 1)X(1, 2)-1.6X(1, 2)+0.3X(1, 2)X(1, 1)+0.09X(1, 1)-0.48X(1, 1)-1.6X(1, 2)-0.48X(1, 1)+2.56 = 0.6X(1, 1)X(1, 2)-2.2X(1, 2)-0.87X(1, 1)+2.56
[0104](4) (X (2,2)+0.2X (1,2)+0.3X (2,I)-1.1)2= X (2, 2) 2+0.2X (I, 2)X (2,2)+0.3X(2, I) X (2,2)-1.1X (2,2)+0.2X(2, 2)X(1, 2)+0.04X(1, 2)2+0.06X(2, I)X(l, 2)-0.22X(1, 2)+0.3X(2, 2) X (2,1)+0.06X(1, 2) X (2,1)+0.09X(2, I) X (2,I)-0.33X(2, 1)-1.1X(2, 2)-0.22X(1, 2)-0.33X(2, 1)+1.21 = X (2,2)+0.2X(1, 2)X (2,2)+0.3X(2, I) X (2,2)-1.1X (2,2)+0.2X(2, 2)X(1, 2)+0.04X(1, 2)+0.06X(2, I)X (1,2) -0.22X (1,2) +0.3X (2,2) X (2,I) +0.06X (1,2) X (2,I) +0.09X (2,I) -0.33X (2,I)-1.1X(2,2)-0.22X(1, 2)-0.33X(2, 1)+1.21 = 0.4X(1, 2)X(2,2)+0.6X(2, I)X(2,2)+0.12X(2, I)X(l, 2)-1.2X(2, 2)-0.4X(1, 2)-0.57X(2, 1)+1.21
[0105](5) (X(3, 2)+0.2X(2, 2)+0.3X(2, 1)-0.1)2= X (3,2) X (3,2)+0.2X(2, 2)
X (3,2) +0.3X (2,I) X (3,2) -0.1X (3,2) +0.2X (3,2) X (2,2) +0.04X (2,2) X (2,2) +0.06X (2,I)X (2,2)-0.02X(2, 2)+0.3X(3, 2) X (2,1)+0.06X(2, 2) X (2,1)+0.09X(2, I) X (2,I)-0.03X(2, 1)-0.1X (3,2)-0.02X(2, 2)-0.03X(2, 1)+0.01 = X (3,2)+0.2X(2, 2)X (3,2)+0.3X(2, I) X (3,2)-0.1X (3,2)+0.2X(3, 2) X (2,2)+0.04X(2, 2)+0.06X(2, I)X (2,2) -0.02X (2,2) +0.3X (3,2) X (2,I) +0.06X (2,2) X (2,I) +0.09X (2,I) -0.03X (2,I) -0.1X(3,2)-0.02X(2, 2)-0.03X(2, 1)+0.01 = 0.4X(2, 2) X (3,2)+0.6X(2, I) X (3,2)+0.12X(2, I)X (2,2) +0.8X (3,2) +0.03X (2,I) +0.01
[0106](6) (X (1, 3)+0.3X (1, 2)-0.2) 2= X (1, 3 ) X (1, 3 ) + 0.3 X (1, 2 )X(l, 3)-0.2X(1, 3)+0.3X(1, 3)X(1, 2)+0.09X(1, 2)X(1, 2)-0.06X(1, 2)-0.2X(1, 3)-0.06X(1, 2)+0.04 = X(l, 3)+0.3X(1, 2)X(1, 3)-0.2X(1, 3)+0.3X(1, 3)X(1, 2)+0.09X(1,2)-0.06X(1, 2)-0.2X(1, 3)-0.06X(1, 2)+0.04 = 0.6X(1, 2)X(1, 3)+0.6X(1, 3)-0.03X(1, 2)+0.04
[0107](7) (X(2, 3)+0.2X(1, 3)+0.3X(2, 2)-0.3)2= X (2,3) X (2,3)+0.2X(1, 3)
X (2,3) +0.3X (2,2) X (2,3) -0.3X (2,3) +0.2X (2,3) X (1,3) +0.04X (1,3) X (1,3) +0.06X (2,2)X(l, 3)-0.06X(1, 3)+0.3X(2, 3) X (2,2)+0.06X(1, 3) X (2,2)+0.09X(2, 2) X (2,2)-0.09X(2, 2)-0.3X(2, 3)-0.06X(1, 3)-0.09X(2, 2)+0.09 = X (2,3)+0.2X(1, 3)X (2,3)+0.3X(2, 2) X (2,3)-0.3X(2, 3)+0.2X(2, 3)X(1, 3)+0.04X(1, 3)+0.06X(2, 2)X (1,3) -0.06X (1,3) +0.3X (2,3) X (2,2) +0.06X (1,3)
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